6.2 liters of an ideal gas are contained at 3.0 atm and 37 °C. How many moles of this gas are present?
Solution
The ideal gas law states
PV = nRT where
P = pressure
V = volume
n = number of moles of gas
R = gas constant = 0.08 L atm / mol K
T = absolute temperature in Kelvin
Step 1
Convert °C temperature to K
T = °C + 273
T = 37 °C + 273
T = 310 K
Step 2
Solve ideal gas law for number of moles
n = PV / RT
n = ( 3.0 atm x 6.2 L ) / ( 0.08 L atm /mol K x 310 K)
n = 0.75 mol
Answer
There are 0.75 mol of the ideal gas present in the system.
