How to Balance Redox Reactions - Balancing Redox Reactions

10 I^- → 5 I₂ + 10 e^-

16 H⁺ + 2 MnO₄^- + 10 e^- → 2 Mn²⁺ + 8 H₂O

This yields the following final equation:

10 I^- + 10 e^- + 16 H⁺ + 2 MnO₄^- → 5 I₂ + 2 Mn²⁺ + 10 e^- + 8 H₂O

Get the overall equation by canceling out the electrons and H₂O, H⁺, and OH^- that may appear on both sides of the equation:

10 I^- + 16 H⁺ + 2 MnO₄^- → 5 I₂ + 2 Mn²⁺ + 8 H₂O

• Balancing Redox Reactions - Half-Reaction Method
• Balancing Redox Reactions - Separate the Reactions
• Balancing Redox Reactions - Balance the Atoms
• Balancing Redox Reactions - Balance the Charge
• Balancing Redox Reactions - Add the Half-Reactions
• Balancing Redox Reactions - Check Your Work