How to Balance Redox Reactions - Balancing Redox Reactions

2 I^- --> I₂ + 2e^-

5 e^- + 8 H⁺ + MnO₄^- --> Mn²⁺ + 4 H₂O

Now multiple the oxidations numbers so that the two half-reactions will have the same number of electrons and can cancel each other out:

5(2I^- --> I₂ +2e^-)

2(5e^- + 8H⁺ + MnO₄^- --> Mn²⁺ + 4H₂O)

Index: How to Balance Redox Reactions - Balancing Redox Reactions

1. Balancing Redox Reactions - Half-Reaction Method
2. Balancing Redox Reactions - Separate the Reactions
3. Balancing Redox Reactions - Balance the Atoms
4. Balancing Redox Reactions - Balance the Charge
5. Balancing Redox Reactions - Add the Half-Reactions
6. Balancing Redox Reactions - Check Your Work