How to Balance Redox Reactions - Balancing Redox Reactions

Balance the iodine atoms:

2 I^- → I₂

The Mn in the permanganate reaction is already balanced, so let's balance the oxygen:

MnO₄^- → Mn²⁺ + 4 H₂O

Add H⁺ to balance the 4 waters molecules:

MnO₄^- + 8 H⁺ → Mn²⁺ + 4 H₂O

The two half-reactions are now balanced for atoms:

MnO₄^- + 8 H⁺ → Mn²⁺ + 4 H₂O

• Balancing Redox Reactions - Half-Reaction Method
• Balancing Redox Reactions - Separate the Reactions
• Balancing Redox Reactions - Balance the Atoms
• Balancing Redox Reactions - Balance the Charge
• Balancing Redox Reactions - Add the Half-Reactions
• Balancing Redox Reactions - Check Your Work