**Problem:**

A balloon with a volume of 2.0 L is filled with a gas at 3 atmospheres. If the pressure is reduced to 0.5 atmospheres without a change in temperature, what would be the volume of the balloon?

**Solution:**

Since the temperature does not change, Boyle's law can be used. Boyle's gas law can be expressed as:

P

_{i}V

_{i}= P

_{f}V

_{f}

where

P

_{i}= initial pressure

V

_{i}= initial volume

P

_{f}= final pressure

V

_{f}= final volume

To find the final volume, solve the equation for V

_{f}:

V

_{f}= P

_{i}V

_{i}/P

_{f}

V

_{i}= 2.0 L

P

_{i}= 3 atm

P

_{f}= 0.5 atm

V

_{f}= (2.0 L)(3 atm)/(0.5 atm)

V

_{f}= 6 L/0.5

V

_{f}= 12 L

**Answer:**

The volume of the balloon will expand to 12 L.