Ideal Gas Law - Worked Chemistry Problems

You may wish to refer to the General Properties of Gases to review concepts and formulae related to ideal gases.

Problem

2.50 g of XeF₄ gas is placed into an evacuated 3.00 liter container at 80°C. What is the pressure in the container?

Solution

PV = nRT, where P is pressure, V is volume, n is number of moles, R is the gas constant, and T is temperature.

P=?
V = 3.00 liters
n = 2.50 g XeF₄ x 1 mol/ 207.3 g XeF₄ = 0.0121 mol
R = 0.0821 l·atm/(mol·K)
T = 273 + 80 = 353 K

Plugging in these values:

P = nRT/V

P = 00121 mol x 0.0821 l·atm/(mol·K) x 353 K / 3.00 liter

P = 0.117 atm

Answer

0.117 atm

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